How much heat is necessary to raise the temperature of 3,439 grams of lead, from 20°C solid lead to all liquid at 327°C?
how much heat ir required to melt 100g of gold in 1063 celsius?
how much heat energy must be applied to 100 grams of Lead to raise its temperature 20° C?
To calculate the amount of heat required to raise the temperature of a substance, you can use the following equation:
Q = m * c * ΔT
Where:
Q is the heat energy (in joules)
m is the mass of the substance (in grams)
c is the specific heat capacity of the substance
ΔT is the change in temperature (final temperature - initial temperature)
To calculate the heat energy required for lead, we need to know its specific heat capacity. The specific heat capacity of lead is approximately 0.13 J/g°C.
Given:
Mass of lead (m) = 3439 grams
Initial temperature (T1) = 20°C
Final temperature (T2) = 327°C
Specific heat capacity of lead (c) = 0.13 J/g°C
Step 1: Calculate the change in temperature (ΔT)
ΔT = T2 - T1
ΔT = 327°C - 20°C = 307°C
Step 2: Calculate the heat energy (Q)
Q = m * c * ΔT
Q = 3439 g * 0.13 J/g°C * 307°C
Now we can calculate Q:
Q ≈ 141,921.73 J
Therefore, roughly 141,922 joules of heat energy are required to raise the temperature of 3,439 grams of lead from 20°C to 327°C.