algebra

use the remainder theorem to find the remainder when P(x)=x^4-9x^3-5x^2-3x+4 is divided by x+3

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  1. Just plug in x = -3 and the value P(-3) is the remainder when P(x) is divided by (x+3).

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  2. -3[1 -9 -5 -3 4
    -3 36 -93 288
    1 -12 32 -96 292

    x^3-12x^2+31x-96
    x+3[x^4-9x^3-5x^2-3x+4
    -(x^4+3x^3)
    -12x^3-5x^2
    -(-12x^3-36^2
    31x^2-3x
    (-31x^2+93x)
    -96x+4
    -(-96-288)
    292

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