(cotx + cscx(1-cosx)= SIN x
To prove that cot(x) + csc(x)(1-cos(x)) = sin(x), we need to simplify the left side of the equation and show that it is equal to the right side.
Let's start by simplifying the left side:
cot(x) + csc(x)(1-cos(x))
Recall that cot(x) is equal to cos(x)/sin(x) and csc(x) is equal to 1/sin(x). Let's substitute these values in:
(cos(x)/sin(x)) + (1/sin(x))(1-cos(x))
Now, let's simplify the expression further:
(cos(x) + (1-cos(x)))/(sin(x))
Using the distributive property, we can simplify the numerator:
(1)/(sin(x))
The equation becomes:
1/sin(x) = sin(x)
Now, let's simplify the right side of the equation:
sin(x)
Since 1/sin(x) is equal to csc(x), the equation becomes:
csc(x) = sin(x)
Therefore, we have proved that cot(x) + csc(x)(1-cos(x)) is equal to sin(x).