How many milliliters of a 0.20 M of glucose (C6H12O6) solution are needed to provide a total of 25.0 g. of glucose?
Molarity(M)= Moles of Solute/Liters of Solution
To find the volume of the glucose solution needed, we can use the formula:
Molarity(M) = Moles of Solute / Liters of Solution
We know the molarity of the glucose solution is 0.20 M and we want to find the volume in milliliters. First, we need to find the number of moles of glucose.
The molecular weight of glucose (C6H12O6) is:
C: 12.01 g/mol
H: 1.008 g/mol
O: 16.00 g/mol
Adding up the atomic weights:
(6 x 12.01 g/mol) + (12 x 1.008 g/mol) + (6 x 16.00 g/mol) = 180.18 g/mol
Now, we can calculate the number of moles of glucose:
Number of moles of glucose = Mass of glucose / Molecular weight of glucose
Number of moles of glucose = 25.0 g / 180.18 g/mol
Next, we can use the molarity formula to find the volume:
Molarity = Moles of Solute / Liters of Solution
0.20 M = (25.0 g / 180.18 g/mol) / Volume in liters
Simplifying the equation:
Volume in liters = (25.0 g / 180.18 g/mol) / 0.20 M
To convert the volume from liters to milliliters, we multiply by 1000:
Volume in milliliters = [(25.0 g / 180.18 g/mol) / 0.20 M] * 1000
Let's calculate this:
Volume in milliliters = [(25.0 g / 180.18 g/mol) / 0.20 M] * 1000
= 69.6 mL
Therefore, approximately 69.6 milliliters of a 0.20 M glucose solution are needed to provide a total of 25.0 g of glucose.
To solve this problem, we need to use the formula for molarity:
Molarity (M) = Moles of Solute / Liters of Solution
We are given the molarity of the glucose solution (0.20 M), and we need to find the number of milliliters needed to provide 25.0 g of glucose.
First, let's calculate the moles of glucose in 25.0 g. We know the molar mass of glucose is 180.16 g/mol.
Moles of glucose = mass of glucose / molar mass
Moles of glucose = 25.0 g / 180.16 g/mol
Now we have the moles of glucose.
Next, we can use the molarity formula to find the volume of the solution.
Molarity (M) = Moles of Solute / Liters of Solution
Rearranging the formula, we have:
Liters of Solution = Moles of Solute / Molarity
We have the moles of glucose and the molarity of the solution, so we can substitute these values into the formula:
Liters of Solution = (moles of glucose) / (molarity)
Finally, since we want to find the volume in milliliters, we need to convert liters to milliliters. There are 1000 milliliters in 1 liter.
Therefore, the final step is to multiply the liters of solution by 1000:
Milliliters of Solution = (Liters of Solution) x 1000
By using these calculations, we can determine the number of milliliters of the 0.20 M glucose solution needed to provide a total of 25.0 g of glucose.
Right.
mols = grams/molar mass.
You know grams and molar mass; solve for mols.
Then mols = M x L
Solve for L and convert to mL.