This is my HW problem;

I'm thinking of a number. When I double my number, subtract five, and then add my original number, I get one. What's my number?

cmon its 2

2n-5 +n=1

3n=6
n=2

Andrew guess what, I was a tid bit busy. So spare the tude. thanks Bobpursley.

Sarah -- you posted this question three times in 13 minutes. It's not surprising that your demanding "tude" in this post raised andrew's hackles.

damn, math drama. That's a first.

To solve this problem, we can break it down into steps and use algebra to find the answer. Let's call the unknown number "X."

We know that when you double the number, subtract five, and then add the original number, the result is one. So we can set up an equation based on the given information:

2X - 5 + X = 1

To solve for X, we need to simplify the equation by combining like terms:

3X - 5 = 1

Next, we isolate the variable by getting rid of the constant term -5. We can do this by adding 5 to both sides:

3X - 5 + 5 = 1 + 5
3X = 6

Now, we need to solve for X by dividing both sides of the equation by 3:

3X/3 = 6/3
X = 2

Therefore, the number you're thinking of is 2.