Calculate the mass in grams of 2.50 mol iron(II) hydroxide.
A. 29.5 g Fe(OH)2
B. 184.5 g Fe(OH)2
C. 225 g Fe(OH)2
D. 3.38 x 10-2 g Fe(OH)2
C
right.
To determine the mass in grams of 2.50 mol iron(II) hydroxide, you can use the molar mass of the compound. The molar mass is the sum of the atomic masses of all the atoms in the formula.
The molecular formula for iron(II) hydroxide is Fe(OH)2.
To calculate the molar mass of Fe(OH)2, we need to add up the atomic masses of iron (Fe), oxygen (O), and hydrogen (H) in the compound.
Looking up the atomic masses on the periodic table, we find:
- Atomic mass of iron (Fe) = 55.85 g/mol
- Atomic mass of oxygen (O) = 16.00 g/mol
- Atomic mass of hydrogen (H) = 1.01 g/mol
Fe(OH)2 consists of one iron atom (Fe) and two hydroxide ions (OH), where each hydroxide ion contains one oxygen atom (O) and one hydrogen atom (H).
Therefore, the molar mass of Fe(OH)2 can be calculated as follows:
Molar mass of Fe(OH)2 = (1 x atomic mass of Fe) + (2 x atomic mass of O) + (2 x atomic mass of H)
Molar mass of Fe(OH)2 = (1 x 55.85 g/mol) + (2 x 16.00 g/mol) + (2 x 1.01 g/mol)
= 55.85 g/mol + 32.00 g/mol + 2.02 g/mol
= 89.87 g/mol
Now, to find the mass in grams of 2.50 mol of Fe(OH)2, we can use the following formula:
Mass of Fe(OH)2 in grams = molar mass of Fe(OH)2 x number of moles
Mass of Fe(OH)2 in grams = 89.87 g/mol x 2.50 mol
= 224.675 g
Therefore, the mass of 2.50 mol of Fe(OH)2 is approximately 224.675 grams.
Since the answer options are rounded and may vary slightly due to different molar mass calculations, the closest option to this result is C. 225 g Fe(OH)2.