A person pulls a toboggan for a distance of 20.0 m along the snow with a rope directed 15.0° above the snow. The tension in the rope is 63.0 N.
You have described the situation. Now what is the question?
This previously asked complete question may help, although the numbers are different.
http://www.jiskha.com/display.cgi?id=1203443096
To find the force component of the tension in the rope directed along the snow, we can use trigonometry. The force component along the snow is given by:
Force component (along the snow) = Tension x cosine(angle)
Where:
- Tension is the tension in the rope (63.0 N)
- Angle is the angle above the snow (15.0°)
Plugging in the values, we have:
Force component (along the snow) = 63.0 N x cosine(15.0°)
To calculate the force component, we need to find the cosine of 15.0°. Let's do that:
cosine(15.0°) = 0.9659
Now we can substitute the values into the formula:
Force component (along the snow) = 63.0 N x 0.9659
Calculating this, we get:
Force component (along the snow) = 60.757 N
So, the force component of the tension in the rope directed along the snow is approximately 60.757 N.