Which of these are balenced?
2 C4H10( g) + 13 O2( g)h8 CO2( g) + 10 H2O(l)
4 C6H7N5O16(s) + 19 O2( g)h24 CO2( g)
+ 20 NO2( g) + 14 H2O(g)
I don't understand this anyhelp would be greatly appreciated.
To determine whether the given chemical equations are balanced, we need to ensure that there are an equal number of atoms of each element on both sides of the equation.
Let's start with the first equation:
2 C4H10(g) + 13 O2(g) → 8 CO2(g) + 10 H2O(l)
To balance this equation, we need to compare the number of carbon (C) atoms on both sides of the equation. We have 2 C4H10 on the left side, which means we have 8 carbon atoms. On the right side, we have 8 CO2, which also contains 8 carbon atoms. So the carbon atoms are balanced.
Next, let's look at the hydrogen (H) atoms. On the left side, we have 10 hydrogen atoms from 2 C4H10, and on the right side, we have 10 hydrogen atoms from 10 H2O. So the hydrogen atoms are also balanced.
Finally, we can check the oxygen (O) atoms. On the left side, we have 13 O2 molecules, which contain 26 oxygen atoms. On the right side, we have 8 CO2, which contains 16 oxygen atoms, and 10 H2O, which also contains 10 oxygen atoms. In total, we have 26 oxygen atoms on the right side, balancing the left side.
Therefore, the first equation is balanced.
Now let's move on to the second equation:
4 C6H7N5O16(s) + 19 O2(g) → 24 CO2(g) + 20 NO2(g) + 14 H2O(g)
To balance this equation, we'll start by comparing the carbon (C) atoms. On the left side, we have 4 units of C6H7N5O16, giving us 4 * 6 = 24 carbon atoms. On the right side, we have 24 CO2 molecules, which also contain 24 carbon atoms. So the carbon atoms are balanced.
Next, let's look at the hydrogen (H) atoms. On the left side, we have 4 units of C6H7N5O16, resulting in 4 * 7 = 28 hydrogen atoms. On the right side, we have 14 H2O molecules, which contain 14 * 2 = 28 hydrogen atoms. Thus, the hydrogen atoms are balanced.
Finally, we can check the oxygen (O) atoms. On the left side, we have 4 units of C6H7N5O16, resulting in 4 * 16 = 64 oxygen atoms. On the right side, we have 24 CO2, which contains 24 * 2 = 48 oxygen atoms, and 20 NO2, which contains 20 * 2 = 40 oxygen atoms. In total, we have 48 + 40 = 88 oxygen atoms on the right side, which exceeds the 64 on the left side.
Therefore, the second equation is not balanced.
To balance the equation, we can add a coefficient in front of the O2 on the left side to adjust the number of oxygen atoms. Let's try this:
4 C6H7N5O16(s) + 19 O2(g) → 24 CO2(g) + 20 NO2(g) + 14 H2O(g)
To balance the oxygen atoms, we need 88/2 = 44 O2 molecules on the left side. And this will give us:
4 C6H7N5O16(s) + 44 O2(g) → 24 CO2(g) + 20 NO2(g) + 14 H2O(g)
Now, if we recheck the carbon, hydrogen, and oxygen atoms, we will find that they are all balanced.
Therefore, the corrected equation is balanced.
I hope this explanation helps you understand how to balance chemical equations. If you have any more questions, feel free to ask!