chem

You have a large amount of 7.50M stock solution. You need 1.80L of 3.00M solution for an experiment. How would you prepare the desired solution without wasting any stock solution?

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  1. The easiest way to work the problem is to use the dilution formula of
    c1v1 = c2v2
    7.5*v1 = 3.00*1.80L
    v1 = 3.00*1.80/7.5 = 0.72L or 720 mL of stock. However, do you have a 1.80 L volumetric flask? Probably not. So I would use a 2.0L volumetric flask and
    7.5*v1 = 3.00*2
    and v1 = about 800 mL. You would measure 800 mL of the stock, add to the 2.0 L volumetric flask, and add water to the mark on the flask.

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