Help me find my percent yield for my witting reaction experiment....
The weight of my final product was: 0.13
I put 0.40 g of benzyltriphenylphosphonium chloride, 0.23 g of 9-anthraldehyde and 1.0ml DMF and 0.5ml of aqueous sodium hydroxide into the flask at the start of the experiment
How do I get a percent yield from this data???
8ml of a mixture of 1:1 propanol and water was also added... Idk if that's important
benzyltriphenylphosphonium chloride mol weight is 388.88
9-anthraldehyde mol weight is 206.24
In my book it also says the density of sodium hydroxide 50% is 1.5 gml
After filtration my product was 0.23
My FINAL product was 0.13
This is a limiting reagent problem.
1. Write the equation and balance it, at least for the major products (meaning you probably can exclude NaOH, H2O, etc).
2. Convert each to mols
3. Using the coefficients in the balanced equation convert mols of each of the reactants to mols of the product.
The reactant producing the FEWEST mols of the product will the one you use.
4. Using the smallest value for the product, convert mols to g. g = mols x molar mass. That is the theoretical yield (TY). The actual yield (AY) is 0.13 what? grams?
%yield = (AY/TY)*100 =
5. %yield = (ac
To calculate the percent yield for your Wittig reaction experiment, you'll need to use the following steps:
Step 1: Calculate the theoretical yield.
To do this, you need to determine the limiting reagent, which is the reactant that is completely consumed in the reaction. In this case, we'll compare the amount of benzyltriphenylphosphonium chloride and 9-anthraldehyde to determine the limiting reagent.
First, convert the given masses of benzyltriphenylphosphonium chloride and 9-anthraldehyde to moles using their molecular weights:
moles of benzyltriphenylphosphonium chloride = 0.40 g / 388.88 g/mol
moles of 9-anthraldehyde = 0.23 g / 206.24 g/mol
Next, calculate the ratio of moles of each reactant to their stoichiometric coefficient in the balanced chemical equation for the reaction:
Benzyltriphenylphosphonium chloride: 1 mole (stoichiometric coefficient: 1)
9-anthraldehyde: 1 mole (stoichiometric coefficient: 1)
Since the ratio is equal for both reactants, neither is limiting, and the reactants are in a 1:1 ratio. Thus, the limiting reagent is determined by the reactant that has a smaller number of moles.
Step 2: Calculate the amount of product produced by the limiting reagent.
Using the stoichiometry from the balanced chemical equation, you can determine the number of moles of the product formed. Since the limiting reactant and the product are in a 1:1 ratio, the moles of product formed will be equal to the moles of the limiting reactant.
Step 3: Convert the moles of product to grams.
Multiply the moles of product from step 2 by the molecular weight of the product to get the theoretical yield in grams.
Step 4: Calculate the percent yield.
Divide the actual yield (weight of the final product) by the theoretical yield, then multiply by 100 and you will get the percent yield.
Note: The information about the density of sodium hydroxide and the addition of the mixture of propanol and water is not relevant for calculating the percent yield.
If you provide the balanced chemical equation for the Wittig reaction, I can help you further with the calculations.