In an electrical circuit, the current passing through a conductor varies inversely with the resistance. Suppose that when the current is 2A (amperes), the resistance is 115ohms. What is the resistance when the current is 5A ?
V = I*R = 2 * 115 = 230 Volts = Applied
voltage.
R = V/I = 230/5 = 46 Ohms.
To find the resistance when the current is 5A, we can use the concept of inverse variation. Inverse variation means that as one variable increases, the other variable decreases, and vice versa, while their product remains constant.
In this case, we know that the current (I) and the resistance (R) are inversely proportional, which can be expressed as:
I ∝ 1/R
We can then write the proportionality equation as:
I1 / R1 = I2 / R2
Where I1 and R1 are the initial values of current and resistance, and I2 and R2 are the new values.
Given that when the initial current (I1) is 2A, the resistance (R1) is 115Ω, and we need to find the resistance (R2) when the current is 5A:
2A / 115Ω = 5A / R2
To find R2, we can cross multiply:
2 * R2 = 115 * 5
Now we can solve for R2:
R2 = (115 * 5) / 2
R2 = 575 / 2
R2 = 287.5Ω
Therefore, when the current is 5A, the resistance is approximately 287.5Ω.