Ok I get most of the problems except for these last two.
x^2-16=0
and
x^2=36
I seem to have trouble with the simplest of problems and none at all with the hard ones.
These follow the pattern of
(x+number)(x-number) when the number is a perfect square. So
(x+4)(x-4) is the first.
Rearrange the second one to
X^2 - 36 = 0 and factor the same way.
Woo! Thanks a lot DrBob.
No worries! I'll explain step-by-step how to solve these two problems:
1. x^2 - 16 = 0
To solve this equation, we can start by moving the constant term (in this case, -16) to the other side of the equation. To do that, we add 16 to both sides:
x^2 = 16
Now, to isolate x, we need to take the square root of both sides of the equation:
√(x^2) = √16
Keep in mind that when taking the square root, we consider both the positive and negative roots. So we have:
x = ±√16
Simplifying the square root of 16 gives us:
x = ±4
So the solution to the equation x^2 - 16 = 0 is x = ±4.
2. x^2 = 36
Similar to the first equation, we start by taking the square root of both sides to isolate x:
√(x^2) = √36
Again, considering both positive and negative roots:
x = ±√36
The square root of 36 simplifies to:
x = ±6
Therefore, the solution to the equation x^2 = 36 is x = ±6.
It's completely normal to face challenges with certain problems while finding others relatively easier. With practice and understanding the underlying concepts, you'll become more comfortable with a wider range of problems.