The distance btwn two stations A and B is 230km.two motrcyclst start simultaneously frm A & B in opposite directn and the distance btwn them aftr 3hour bcm 20km.if the speed of one motorcyclst is 10km hr les thn that of the other,find the speed of the two motorcyclsts

4o nd 30

km/hr is ans plz help to gve dis qustn sltn

2x+1,00000

Let Faster Speed be - X+10 km/hr

and slower-X km/hr
In three hour they covered 230-20=210 km
as we know
Time ×Speed(Relative speed) = distance
3(X +X +10)=210
by solving X=30KM/hr
X+10= 40
ans is 40 km/hr and 30 km/hr.

Thanks.

To find the speed of the two motorcyclists, let's consider the following:

Let the speed of one motorcyclist be x km/hr.
The speed of the other motorcyclist is then x + 10 km/hr (given they have a speed difference of 10 km/hr).

After 3 hours, the distance covered by the first motorcyclist is 3x km (since speed × time = distance).
Similarly, the distance covered by the second motorcyclist is 3(x + 10) km.

According to the problem, the total distance covered by both motorcyclists is 230 km, and the distance between them after 3 hours is 20 km.

So, we can write the following equation:
3x + 3(x + 10) = 230 - 20

We can simplify this equation to solve for x:
3x + 3x + 30 = 210
6x = 210 - 30
6x = 180
x = 180 / 6
x = 30

Therefore, the speed of the first motorcyclist is 30 km/hr, and the speed of the second motorcyclist is 30 + 10 = 40 km/hr.