What volume of a 0.5 M solution is required to prepare 250 mL of a 0.15M solution?

(Note: M = mole per Litre)

Well, if you need to prepare a 0.15 M solution and you have a 0.5 M solution, we need to do some dilution.

Using the formula:

C1V1 = C2V2

Where C1 is the initial concentration, V1 is the initial volume, C2 is the final concentration, and V2 is the final volume, we can solve for V1.

Given:
C1 = 0.5 M
C2 = 0.15 M
V2 = 250 mL

Let's substitute the values into the equation:

(0.5 M)(V1) = (0.15 M)(250 mL)

Now we can solve for V1:

V1 = (0.15 M)(250 mL) / 0.5 M

V1 = (0.0375 moles) / (0.5 moles/L)

V1 = 0.075 L

So, approximately 75 mL of the 0.5 M solution is required to prepare 250 mL of the 0.15 M solution.

Just make sure to dilute it properly and don't confuse it with lemonade!

To calculate the volume of the 0.5 M solution required to prepare 250 mL of a 0.15 M solution, you can use the formula:

C1V1 = C2V2

where:
C1 = initial concentration (0.5 M)
V1 = initial volume (unknown)
C2 = final concentration (0.15 M)
V2 = final volume (250 mL or 0.25 L)

Rearranging the formula to solve for V1, you get:

V1 = (C2 * V2) / C1

Substituting the given values into the formula:

V1 = (0.15 M * 0.25 L) / 0.5 M

V1 = 0.0375 L or 37.5 mL

Therefore, you will need 37.5 mL of the 0.5 M solution to prepare 250 mL of the 0.15 M solution.

To find the volume of a 0.5 M solution required to prepare 250 mL of a 0.15 M solution, we can use the formula:

C1V1 = C2V2

where:
C1 = initial concentration of the solution
V1 = initial volume of the solution
C2 = final concentration of the solution
V2 = final volume of the solution

In this case:
C1 = 0.5 M (concentration of the initial solution)
V1 = ? (volume of the initial solution)
C2 = 0.15 M (desired concentration of the final solution)
V2 = 250 mL (final volume of the solution)

By substituting the given values into the formula, we can solve for V1:

0.5 M * V1 = 0.15 M * 250 mL

Now, let's solve the equation:

V1 = (0.15 M * 250 mL) / 0.5 M

V1 = (0.15 * 250) / (0.5)

V1 = 375 / 0.5

V1 = 750 mL

Therefore, you would require 750 mL of the 0.5 M solution to prepare 250 mL of a 0.15 M solution.

You want to dilute it by a factor of .5/.15, or 3.33 times. So you need one part original, 2.33 parts water to dilute.

What is one part? 250/3.33=75ml
so you need 75 ml of the original solution. Add 75*2.33=175ml water, stir, and label.