# tatiana

A car tire of radius 45cm turns at a constant 14 rads/s. For a point on the edge calculate
a) the tangential V
b) the tangential a
c) the centripetal "a"

work:
a) v= rw
v= .45m * 14 rads/s= 6.3m/s
b) at=alphar
alpha= w/t
I am unsure how to get time?
c) at= w^2r
at= 14^2 * .45
at= 88.2 m/s^2

A bike's wheel has a diameter of 70.0cm. If it is rolling at 4.00 revolutions/ s find the forward velocity of the bike (linear motion). Use rotational equations.

d= .35 (after conversion and dividing by 2)
w= 25.12 rads/s (after conversion)

v=rw
v= (.35)(25.12rad/s)= 8.79
did I use the right concept

On the car tire, if the velocity is constant, the tangential acceleration is zero. Right on the other two. I would have done c with v^2/radius.

Yes. The tangential velocity has to be the same as the velocity at the road surface.

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asked by physics

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