For a single movable pulley with a mechanical advantage of 2, how much rope must be pulled to lift a 150 neuton load 2 meters above the ground?

fgts

To answer this question, we need to understand the concept of mechanical advantage and the formula to calculate the effort required to lift a load using a single movable pulley.

Mechanical advantage (MA) is defined as the ratio of the output force (load) to the input force (effort). In the case of a single movable pulley, the mechanical advantage is equal to 2. This means that the load will be lifted with half the effort compared to lifting it directly.

To calculate the effort required, we can use the formula:

Effort = Load / MA

In this case, the load is given as 150 N and the mechanical advantage is 2. Plugging these values into the formula, we get:

Effort = 150 N / 2 = 75 N

So, the effort required to lift the 150 N load using a single movable pulley with a mechanical advantage of 2 is 75 N.

Now, let's calculate the amount of rope that needs to be pulled to lift the load 2 meters above the ground.

The distance the load is lifted is equal to the distance the effort is pulled. In this case, the load is lifted 2 meters. Therefore, the amount of rope that needs to be pulled is also 2 meters.

Therefore, to lift the 150 N load 2 meters above the ground using a single movable pulley, you would need to pull 2 meters of rope.