A 10.4 kg object oscillates at the end of a vertical spring that has a spring constant of 17500 N/m. The effect of air resistance is represented by the damping coefficient b = 3.00 N¡¤s/m.
You have not asked a question. You have only stated some physical parameters.
There is an equation you can write down for displacement vs. time.
You have not stated the initial amplitude.
To determine the period of oscillation for the given system, we need to consider the mass of the object, the spring constant, and the damping coefficient.
The period T of an oscillating object attached to a spring is given by the equation:
T = 2π√(m/k)
Where:
T is the period in seconds.
π is a mathematical constant approximately equal to 3.14159.
m is the mass of the object in kilograms.
k is the spring constant in Newtons per meter.
Given:
m = 10.4 kg (mass of the object)
k = 17500 N/m (spring constant)
Using the given values, we can calculate the period:
T = 2π√(10.4/17500)
T = 2π√(0.0005943)
T ≈ 2π(0.0244)
T ≈ 0.1534 seconds
Therefore, the period of oscillation for the object is approximately 0.1534 seconds.