Which of the following gases will effuse through a hole in a balloon fastest?

a.Kr
b.NO
c.N2O
d.NO2
e.ArNO2

The one with the lowest mass.

b. NO

The rate of effusion depends on the molar mass of a gas, with lighter gases tending to effuse faster than heavier ones. The molar mass of the gases in this question are as follows:

a. Kr (Krypton) - molar mass = 83.8 g/mol
b. NO (Nitric Oxide) - molar mass = 30.0 g/mol
c. N2O (Nitrous Oxide) - molar mass = 44.0 g/mol
d. NO2 (Nitrogen Dioxide) - molar mass = 46.0 g/mol
e. ArNO2 - This compound is not familiar. Please double-check the options and provide the correct one.

Based on molar mass, the gas with the lowest value (lightest gas) will effuse the fastest. In this case, the lowest molar mass is NO (30.0 g/mol) out of the given options. Therefore, the answer is b. NO.

To determine which gas will effuse through a hole in a balloon fastest, we need to consider the molar mass of each gas. The rate of effusion is inversely proportional to the square root of the molar mass.

Let's calculate the molar masses:

a. Kr (krypton) has a molar mass of approximately 83.8 g/mol.
b. NO (nitric oxide) has a molar mass of approximately 30.0 g/mol.
c. N2O (nitrous oxide) has a molar mass of approximately 44.0 g/mol.
d. NO2 (nitrogen dioxide) has a molar mass of approximately 46.0 g/mol.
e. ArNO2 (aryl nitrite) is not a valid compound and does not have a molar mass.

Now we can compare the molar masses to determine which gas will effuse the fastest. The gas with the lowest molar mass will effuse the quickest.

Comparing the molar masses, we find that NO (30.0 g/mol) has the lowest molar mass among the given options. Therefore, the gas NO will effuse through a hole in a balloon fastest compared to the other gases listed.