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calculus

You are using Newton's method to solve x^3-5x-2=0. If your first guess is X1=2, what value will you calculate for the next approximation X2?

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Anonymous

  1. your equation would be

    xnew = x - (x^3 - 5x - 2)/(3x^2 - 5)

    so for x=2
    xnew = 2 - (8-10-2)/(12-5)
    = 2.5714

    Incidentally, my next 4 answers were

    2.4268029
    2.4143045
    2.4142136 and
    2.4142136 which would be one of the answers correct up to 7 decimal places.

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    Reiny

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