How many grams of dichloromethane result from reaction of 2.62 kg of methane if the yield is 43.5 %?
CH4+2Cl -> CH2Cl2+2HCl
Here is a worked example of a simple stoichiometry problem. You will find the theoretical yield, then multiply that by 0.435.
http://www.jiskha.com/science/chemistry/stoichiometry.html
To determine the number of grams of dichloromethane (CH2Cl2) produced from the given amount of methane (CH4), we need to follow these steps:
1. Convert the mass of methane from kilograms to grams:
2.62 kg * 1000 g/kg = 2620 g
2. Calculate the theoretical yield of dichloromethane:
The balanced chemical equation shows that 1 mole of methane produces 1 mole of dichloromethane.
However, the equation does not directly provide the molar ratio between methane and dichloromethane.
To find the molar ratio, we compare the molecular weights of methane and dichloromethane:
Methane (CH4) has a molar mass of 12.01 g/mol (carbon) + 4 * 1.008 g/mol (hydrogen) = 16.04 g/mol
Dichloromethane (CH2Cl2) has a molar mass of 12.01 g/mol (carbon) + 2 * 35.45 g/mol (chlorine) + 2 * 1.008 g/mol (hydrogen) = 84.93 g/mol
The molar ratio is obtained by dividing the molar masses:
16.04 g/mol CH4 / 84.93 g/mol CH2Cl2 = 0.1887
Therefore, we know that for every mole of methane, we will produce approximately 0.1887 moles of dichloromethane.
3. Calculate the moles of dichloromethane produced:
To find the moles of dichloromethane, we multiply the moles of methane by the molar ratio:
2620 g CH4 * (1 mol CH4 / 16.04 g CH4) * (0.1887 mol CH2Cl2 / 1 mol CH4) = 308.9 mol CH2Cl2
4. Calculate the mass of dichloromethane in grams:
Finally, we convert the moles of dichloromethane to grams by multiplying by its molar mass:
308.9 mol CH2Cl2 * 84.93 g CH2Cl2 / 1 mol CH2Cl2 = 26,231.53 g CH2Cl2
However, the question states that the yield is 43.5%.
Therefore, we need to determine the actual yield by multiplying the theoretical yield by the yield percentage:
26,231.53 g CH2Cl2 * 0.435 = 11,400.24 g CH2Cl2
So, approximately 11,400.24 grams of dichloromethane would result from the reaction of 2.62 kg of methane if the yield is 43.5%.