How many moles of Cu are produced when 0.25 moles of Cu2Se are completely reduced by an excess of hydrogen gas?

Question

Create a visually straightforward and educational image showing the process of Cu2Se being reduced by hydrogen gas. Illustrate 0.25 moles of Cu2Se molecule represented as two copper atoms and one selenium atom on the left side. On the right side, depict an equivalent amount of copper Cu molecules, produced as a result of the reduction process. Emphasize the conversion process by symbolizing the excess of hydrogen gas, but remember to not use any text or numbers in the composition.

How many moles of Cu are produced when 0.25 moles of Cu2Se are completely reduced by an excess of hydrogen gas?

Answer 1

you have two molecules of Cu for every molecule of Cu2Se

so
2 * .25 = .5 mol

Answer 2

Oh, it's a mole party! So, let's see. Given that we have 0.25 moles of Cu2Se, we can check out the balanced equation to find the mole ratio. According to my calculations, the balanced equation is:

Cu2Se + H2 → 2Cu + H2Se

So, for every 1 mole of Cu2Se, we get 2 moles of Cu. If we have 0.25 moles of Cu2Se, we just need to double that number to find the number of moles of Cu. Mathematically, it would be like 0.25 moles of Cu2Se multiplied by 2 moles of Cu per 1 mole of Cu2Se.

0.25 moles of Cu2Se x 2 moles of Cu/1 mole of Cu2Se = 0.5 moles of Cu

So, we have got ourselves 0.5 moles of Cu making their grand entrance!

Answer 3

To determine the number of moles of Cu produced, we need to look at the balanced equation for the reaction between Cu2Se and hydrogen gas (H2):

Cu2Se + 2H2 -> 2Cu + H2Se

From the equation, we can see that 1 mole of Cu2Se reacts to produce 2 moles of Cu. Therefore, we can set up a ratio:

1 mol Cu2Se : 2 mol Cu

Now, we can calculate the number of moles of Cu produced:

0.25 mol Cu2Se x (2 mol Cu / 1 mol Cu2Se) = 0.5 mol Cu

Therefore, 0.25 moles of Cu2Se will produce 0.5 moles of Cu when completely reduced by an excess of hydrogen gas.

Answer 4

To determine the number of moles of Cu produced when 0.25 moles of Cu2Se are completely reduced, we need to use the balanced chemical equation for the reaction and the stoichiometry between the reactants and products.

The balanced chemical equation for the reaction can be written as follows:

Cu2Se + H2 -> 2Cu + H2Se

From the equation, we can see that 1 mole of Cu2Se reacts to produce 2 moles of Cu. Therefore, we can set up a simple conversion factor:

1 mole Cu2Se = 2 moles Cu

To calculate the number of moles of Cu produced from 0.25 moles of Cu2Se, we can use the following calculation:

0.25 moles Cu2Se x (2 moles Cu / 1 mole Cu2Se) = 0.5 moles Cu

Therefore, when 0.25 moles of Cu2Se are completely reduced by an excess of hydrogen gas, 0.5 moles of Cu are produced.