In a 2digit no. ,the face value of the digit at the tens place is four times dat of the digit at ones place. If 54 is substrctd frm the no. ,the digit are reversed.find the no.

Ans is 82

t = 4u

10t+u - 54 = 10u+t

10*4u+u-54 = 10u+4u
40u+u-54=14u
26u=52
u=2

so, the number is 82

Thnx..

Sory i don't undrstnd

Plz solve dis qustn again in simple method bcz i didn't undrstnd

To find the number, we can follow these steps:

1. Let's assume the digit at the one's place is 'x'.
2. According to the given condition, the face value of the digit at the tens place is four times that of the digit at the ones place. So, the digit at the tens place would be 4x.
3. The number can be represented as 10(4x) + x = 34x.
4. According to the given condition, when 54 is subtracted from the number, the digits are reversed. So, the reverse of the number is 10x + 4x = 14x.
5. Therefore, 34x - 54 = 14x.
6. Solving this equation, we get x = 2.
7. So, the digit at the ones place is 2, and the digit at the tens place is 4*2 = 8.
8. Hence, the number is 82.