Calculate the grams of solute needed to prepare each of the following. 55.0 ml of a 6.50 hcl solution.

mols HCl needed = M x L = ?

Then mol = grams/molar mass. You know mols and molar mass, solve for grams.

To calculate the grams of solute needed to prepare a solution, you need to know the concentration of the solution (in this case, 6.50 M HCl) and the volume of the solution you want to prepare (in this case, 55.0 mL).

The formula to calculate the grams of solute is:

grams of solute = concentration (mol/L) × volume (L) × molar mass (g/mol)

1. Start by converting the given volume from milliliters to liters:
55.0 mL ÷ 1000 = 0.055 L

2. Multiply the concentration by the volume to get the number of moles of HCl:
6.50 mol/L × 0.055 L = 0.36 mol

3. Determine the molar mass of HCl. Hydrochloric acid (HCl) is composed of hydrogen (H) and chlorine (Cl) atoms. The atomic mass of hydrogen is 1.0078 g/mol, and the atomic mass of chlorine is 35.453 g/mol. Adding these together gives a molar mass of 36.4608 g/mol.

4. Multiply the moles of HCl by the molar mass to get the grams of HCl:
0.36 mol × 36.4608 g/mol = 13.1269 g

Therefore, 55.0 mL of a 6.50 M HCl solution would require 13.13 grams of HCl.