The wheels of a midsize car exert a force of 2100 N backward on the road to accelerate the car in the forward direction. If the force of friction including air resistance is 250 N and the acceleration of the car is 1.80 m/s2, what is the mass of the car plus its occupants?
4.
netforce=m*a
2100-250=m*1.8 solve for mass m.
1027
To find the mass of the car plus its occupants, we can use Newton's second law of motion:
Force (F) = mass (m) × acceleration (a)
Rearranging the equation, we get:
mass (m) = Force (F) / acceleration (a)
Given that the force exerted by the wheels is 2100 N and the acceleration is 1.80 m/s², we can substitute these values into the equation:
mass = 2100 N / 1.80 m/s²
mass = 1166.67 kg
Therefore, the mass of the car plus its occupants is approximately 1166.67 kg.
To find the mass of the car plus its occupants, we can use Newton's second law of motion, which states that the net force acting on an object is equal to the product of its mass and acceleration.
Step 1: Determine the net force acting on the car.
The net force is the difference between the force exerted by the wheels and the force of friction, given by:
Net force = Force exerted by wheels - Force of friction
Net force = 2100 N - 250 N
Net force = 1850 N
Step 2: Apply Newton's second law of motion.
According to Newton's second law, the net force (1850 N) is equal to the product of the mass (m) of the car plus its occupants and the acceleration (1.80 m/s^2).
Net force = mass * acceleration
1850 N = m * 1.80 m/s^2
Step 3: Solve for mass (m).
Divide both sides of the equation by 1.80 m/s^2 to isolate the mass:
m = 1850 N / 1.80 m/s^2
m ≈ 1027.78 kg
Therefore, the mass of the car plus its occupants is approximately 1027.78 kg.