What is the mole fraction sodium acetate of a solution made by adding 0.145 g of sodium acetate to 119 ml water?

mol NaAc = grams/molar mass

mol H2O = grams/molar mass. I would assume grams = 119 g.
XNaAc = mols NaAc/total mols.

To find the mole fraction of sodium acetate in the solution, we first need to determine the number of moles of sodium acetate and water in the solution.

Step 1: Calculate the number of moles of sodium acetate.
We can use the formula:

Number of moles = mass / molar mass

The molar mass of sodium acetate (CH3COONa) is:
(1 x 22.99) + (2 x 12.01) + (3 x 16.00) + 23.00 = 82.03 g/mol

Number of moles of sodium acetate = 0.145 g / 82.03 g/mol = 0.00177 mol

Step 2: Calculate the number of moles of water.
We can use the formula:

Number of moles = volume (in liters) / molar volume

The molar volume of water is 18.01528 cm³/mol.

Number of moles of water = (119 ml / 1000) L / 18.01528 cm³/mol = 0.0066 mol

Step 3: Calculate the mole fraction of sodium acetate.
The mole fraction of sodium acetate can be calculated using the formula:

Mole fraction = moles of component / total moles

Mole fraction of sodium acetate = 0.00177 mol / (0.00177 mol + 0.0066 mol) = 0.211

Therefore, the mole fraction of sodium acetate in the solution is approximately 0.211.

To find the mole fraction of sodium acetate in the solution, we need to calculate the moles of sodium acetate and water separately.

Step 1: Calculate the moles of sodium acetate:
The molar mass of sodium acetate (NaC2H3O2) is:
Na: 22.99 g/mol
C: 12.01 g/mol
H: 1.01 g/mol
O: 16.00 g/mol

Total molar mass = 22.99 + (12.01 * 2) + (1.01 * 3) + (16.00 * 2) = 82.03 g/mol

The moles of sodium acetate can be calculated by dividing the given mass by the molar mass:
moles of sodium acetate = 0.145 g / 82.03 g/mol = 0.00177 mol

Step 2: Calculate the moles of water:
Since the volume is given in milliliters, we need to convert it to liters:
volume of water = 119 ml / 1000 ml/L = 0.119 L

The moles of water can be calculated by multiplying the volume by the density of water:
moles of water ≈ volume of water * density of water ≈ 0.119 L * 55.6 mol/L ≈ 0.00663 mol

Step 3: Calculate the mole fraction of sodium acetate:
The mole fraction of sodium acetate is defined as the moles of sodium acetate divided by the total moles of all components in the solution.

moles of sodium acetate = 0.00177 mol
moles of water = 0.00663 mol

Total moles of all components = moles of sodium acetate + moles of water
= 0.00177 mol + 0.00663 mol
= 0.0084 mol

The mole fraction of sodium acetate = moles of sodium acetate / total moles of all components
= 0.00177 mol / 0.0084 mol
≈ 0.2119

Therefore, the mole fraction of sodium acetate in the solution is approximately 0.2119.