A pressurized can of whipped cream has an internal pressure of 1.080 atm at 25°C. If it is placed in a freezer at -8°C, what is the new value for its internal pressure (in atmospheres)?
Hmmmm. What is the freezing temperature of the liquid in the can? I bet at -8, it is frozen. how much did it expand (after all, creame is mainly water and fat in an emulsion). So my point is, you can't assume the gas contents in the can have the same volume, due to the liquid expansion. But neglecting that reality.
P1/T1=P2/T2 temps in kelvins
So i tried (1.080)(-8)=(P)(265) and I got -30.67 but its no correct. What am I doing wrong?
A pressurized can of whipped cream has an internal pressure of 1.080 atm at 25°C. If it is placed in a freezer at -8°C, what is the new value for its internal pressure (in atmospheres)?
So i tried (1.080)(-8)=(P)(265) and I got -30.67 but its no correct. What am I doing wrong?
You didn't use kelvin for T.
1) Consider (P1V1)/T1 = (P2V2)/T2
Volume is constant so its P1/T1 = P2/T2
2) Convert C to K
3) Plug in
(Pressure and temperature have an inverse relationship unlike the direct relationship between pressure and volume.)
To calculate the new internal pressure of the can of whipped cream after being placed in the freezer, we can use the ideal gas law. The ideal gas law is represented by the equation:
PV = nRT
Where:
P = Pressure
V = Volume
n = Number of moles
R = Ideal Gas Constant
T = Temperature
We can rearrange the ideal gas law equation to isolate pressure (P):
P = (nRT) / V
Since the number of moles and volume of the can remain constant, we can simplify the equation to:
P = kT
Where k is a constant.
To find the new pressure, we need to convert the temperatures to Kelvin since the ideal gas law requires temperatures in Kelvin.
To convert any temperature from Celsius to Kelvin, we need to add 273.15.
So, the initial temperature of 25°C would be (25 + 273.15) K = 298.15 K.
Similarly, the freezer temperature of -8°C would be (-8 + 273.15) K = 265.15 K.
Now, we can use the formula P = kT to find the new pressure:
Initial pressure (P1) = 1.080 atm
Initial temperature (T1) = 298.15 K
New temperature (T2) = 265.15 K
Using the formula:
P2 = (P1 * T2) / T1
Plug in the values:
P2 = (1.080 atm * 265.15 K) / 298.15 K
Now, do the calculation:
P2 = 0.958 atm
Therefore, the new value for the internal pressure of the can of whipped cream, when placed in the freezer at -8°C, is approximately 0.958 atmospheres.