A landscaper is designing a flower garden in the shape of a trapezoid. She wants the shorter base to be 3 yards greater than the height and the linger base to be 7 yards greater than the height. She wants the area to be 295 square yards. The situation is molded by the equation h^2+5h=295. Use quadratic formula to find the height that will give the desired area. Round to the nearest hundredth of a yard.

Could someone please explain.

I got 14.86 yards not sure if right

14.86 years is THE CORRECT ANSWER i took the test.

To find the height that will give the desired area of a trapezoid-shaped flower garden, you can use the given equation: h^2 + 5h = 295.

To solve this quadratic equation, you can rearrange it into a standard form: h^2 + 5h - 295 = 0.

Now, you can use the quadratic formula, which states that for the quadratic equation ax^2 + bx + c = 0, the solutions are given by:

x = (-b ± √(b^2 - 4ac)) / (2a)

In this case, a = 1, b = 5, and c = -295. Plugging these values into the quadratic formula, we get:

h = (-5 ± √(5^2 - 4(1)(-295))) / (2(1))

Simplifying the equation:

h = (-5 ± √(25 + 1180)) / 2

h = (-5 ± √1205) / 2

To find the approximate values of h, we need to calculate the square root of 1205, which is approximately equal to 34.71.

So, substituting this value:

h = (-5 ± 34.71) / 2

Therefore, we have two possible solutions:

1. h = (-5 + 34.71) / 2 ≈ 29.71 / 2 ≈ 14.86

2. h = (-5 - 34.71) / 2 ≈ -39.71 / 2 ≈ -19.86

Since height cannot be negative, we discard the second solution.

Therefore, the height that will give the desired area, rounded to the nearest hundredth of a yard, is approximately 14.86 yards.

To solve the equation h^2 + 5h = 295 for the height h, we can use the quadratic formula. The quadratic formula states that for an equation of the form ax^2 + bx + c = 0, the solutions for x can be found using the formula:

x = (-b ± √(b^2 - 4ac)) / (2a)

In our equation h^2 + 5h = 295, a = 1 (the coefficient of h^2), b = 5 (the coefficient of h), and c = -295. Applying these values to the quadratic formula, we get:

h = (-5 ± √(5^2 - 4(1)(-295))) / (2(1))

Simplifying further:

h = (-5 ± √(25 + 1180)) / 2

h = (-5 ± √(1205)) / 2

Now we can calculate the two possible solutions for h:

h1 = (-5 + √(1205)) / 2

h2 = (-5 - √(1205)) / 2

Rounding these values to the nearest hundredth of a yard, we can determine the height that will give the desired area.