What volume of a 6.0 M NaOH solution would you need to prepare 250.0 milliliters of a 3.0 M NaOH solution?
250 milliliters = 0.25 L;
To make a 3.0 M NaOH solution from 6.0 M NaOH, you need equal parts of water and NaOH solution
You need 0.25 Liters of the solution, so you need 1/2 * 0.25 = 125 milliliters 6.0 M NaOH, and 125 milliliters water
To determine the volume of a 6.0 M NaOH solution needed to prepare 250.0 milliliters of a 3.0 M NaOH solution, we can use the equation:
M₁V₁ = M₂V₂
Where:
M₁ is the initial concentration (6.0 M)
V₁ is the initial volume (unknown)
M₂ is the final concentration (3.0 M)
V₂ is the final volume (250.0 mL)
Rearranging the equation, we can solve for V₁:
V₁ = (M₂ * V₂) / M₁
Substituting the given values, we have:
V₁ = (3.0 M * 250.0 mL) / 6.0 M
V₁ = (750.0 mL) / 6.0
V₁ ≈ 125.0 mL
So, you would need approximately 125.0 milliliters of the 6.0 M NaOH solution to prepare 250.0 milliliters of a 3.0 M NaOH solution.