In each reaction, calculate the moles of product (in parentheses) when 3.00 moles of each reactant is used.
A: 4Li+O2 = 2Li2O (Li2O)
B: Fe2O3+3H2 = 2Fe+3H2O (Fe)
C: Al2S3+6H2O = 2Al(OH)3+3H2S (H2S)

Please show work, Thanks

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  1. a. if you have 3 moles of O2, 3 moles of Li, you are limited by the Li. You should get then the mole ratio of product to Li (2/4) times the moles of Li, or 2/4*3 moles Li2O

    b. You will be limited by three moles of H2. You get then 2Fe, and 3H2o

    c. you will be limited by the H2o, so you get 1 aluminum hydroxide, and 1.5 H2S moles

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