Use the definition of logarithm to simplify each expression.

(a) log6b(6b)
(b)log8b((8b)^6)
(c)log11b((11b)^-9)

by definition logx(x) = 1 because x^1 = x

log6b(6b) = 1
log8b((8b)^6) = 6*log8b(8b) = 6*1 = 6
similarly,
log11b((11b)^-9) = -9