A(n) 95.7 kg boxer has his first match in the Canal Zone with gravitational acceler- ation 9.782 m/s2 and his second match at the North Pole with gravitational accelera- tion 9.832 m/s2.

a) What is his mass in the Canal Zone? Answer in units of kg
b) What is his weight in the Canal Zone? Answer in units of N
c) What is his mass at the North Pole? Answer in units of kg
d) What is his weight at the North Pole? Answer in units of N

Mass never changes. It is always 95.7 kg

Weight = mass * g, where g is the acceleration of gravity at that point

To answer these questions, we need to understand the concepts of mass and weight.

a) Mass is a measure of the amount of matter in an object and is constant regardless of the location. Therefore, the boxer's mass in the Canal Zone will be the same as his mass anywhere else, which is 95.7 kg.

b) Weight, on the other hand, is the force with which gravity pulls on an object and depends on the gravitational acceleration at that location. It can be calculated using the formula:

Weight = Mass x Acceleration due to gravity

In the Canal Zone, the gravitational acceleration is given as 9.782 m/s^2. Plugging in the values:

Weight = 95.7 kg x 9.782 m/s^2 = 936.4 N

Therefore, his weight in the Canal Zone is 936.4 Newtons.

c) Again, the boxer's mass remains the same regardless of the location. So his mass at the North Pole is still 95.7 kg.

d) To calculate his weight at the North Pole, we use the same formula as before but with the gravitational acceleration value at the North Pole, which is given as 9.832 m/s^2:

Weight = 95.7 kg x 9.832 m/s^2 = 941.1 N

Therefore, his weight at the North Pole is 941.1 Newtons.