Had a few more >.< if you could possibly show steps so i know for future that would be awesome1 thanks!
f(x)=√(lnx+x)
and
f(x)=2^(x^2)
Don't know what the >.< is supposed to be, but from your title, I will assume that you are differentiating.
1.
f(x) = (lnx + x)^(1/2)
f ' (x) = (1/2)(lnx + x)^(-1/2) (1/x + 1)
simplify as needed
2.
f(x) = 2^(x^2)
f ' (x) = ln2(2x) (2^(x^2) )
simplify as needed