Precalculus
I have been trying to verify the below identity. I have been at it for hours, can anyone please help?
1+ cos(theta)/Cos(theta) = tan^2(theta)/sec(theta)1
asked by
George

(1+cos)/cos = sec + 1
= (sec+1)(sec1) / (sec1)
= (sec^21)/ (sec1)
= tan^2/(sec1)
The clue was that sec1 sitting there on the right side.posted by Steve
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Oh now I see your point. I am sorry I should have stated this before. How do I verify that tan^2(theta)/Sec(theta)1 is somehow the same as 1+cos(theta)/Cos(Theta)?