a silver coin has a mass of 2.50g and is analysed for silver by dissolving in dilute nitric acid, and precipitating silver as solid AgCl and weighing this. if the percipitate weighs 2.99g what percentage of silver is in the coin?

If you have AgCl, what percentage of that mass is Ag? I estimate it is about 80 percent, work it out accurately.

what is the mass of silver? Ans: .80(about)*2.99

so what is the percent of silver in the coin? masssilver/mass of coin

To find the percentage of silver in the coin, we need to know the mass of silver in the precipitate (AgCl).

First, we need to determine the molar mass of AgCl. Silver has a molar mass of 107.87 g/mol, and Chlorine has a molar mass of 35.45 g/mol. So, the molar mass of AgCl is:

Ag: 107.87 g/mol
Cl: 35.45 g/mol
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AgCl: 143.32 g/mol

Now, we can use stoichiometry to find the mass of silver (Ag) in the precipitate (AgCl). From the balanced chemical equation:

AgCl(s) → Ag(s) + Cl(g)

The ratio of AgCl to Ag is 1:1 (1 mole of AgCl produces 1 mole of Ag). Therefore, the mass of Ag is also 2.99 g.

Finally, we can calculate the percentage of silver in the coin using the following formula:

% Silver = (mass of Ag / mass of coin) x 100

To find the mass of the coin, we subtract the mass of AgCl from the initial mass of the coin:

mass of coin = mass of AgCl + mass of Ag

mass of coin = 2.99 g + 2.99 g = 5.98 g

% Silver = (2.99 g / 5.98 g) x 100 ≈ 50.0 %

Therefore, the percentage of silver in the coin is approximately 50.0%.