Metals lose electrons under certain conditions to attain a noble-gas electron configuration. How many electrons must be lost by the element Ca?
Is it 2 e^-?
Which noble-gas electron configuration is attained in this process?
argon
radon
krypton
xenon
helium
neon
where is the answer?
I would like to say sorry to jungkook:>
-RM
To determine how many electrons need to be lost by the element Ca (Calcium) to attain a noble-gas electron configuration, we first need to identify the noble-gas electron configuration it aims to achieve.
The noble gases are the elements in Group 18 of the periodic table, including helium (He), neon (Ne), argon (Ar), krypton (Kr), xenon (Xe), and radon (Rn).
To determine the noble-gas electron configuration, we need to locate Ca on the periodic table. Calcium is in Group 2 and has an atomic number of 20.
The noble gas that comes before Ca in the periodic table is argon (Ar), which has an atomic number of 18.
To attain the noble-gas electron configuration of argon, calcium (Ca) needs to lose two electrons.
Therefore, Ca must lose 2 electrons to attain the noble-gas electron configuration of argon.
yes.
Yes it is Ca.
Look at Ca on the periodic chart and take two electrons away. Back up two and identify the noble gas.