Assuming that the smallest measurable wavelength in an experiment is 0.330 fm (femtometers), what is the maximum mass of an object traveling at 157 m·s^–1 for which the de Broglie wavelength is observable?
mass = ? kg
wavelength = h/mv
Substitute wavelength (in meters) with v = m/s and solve for mass in kg.
I don't get the equation.
Assuming that the smallest measurable wavelength in an experiment is 0.650 fm (femtometers), what is the maximum mass of an object traveling at 563 m·s–1 for which the de Broglie wavelength is observable?
To find the maximum mass of an object for which the de Broglie wavelength is observable, we can use the de Broglie wavelength equation:
λ = h / (m * v)
Where:
λ is the wavelength
h is the Planck's constant (6.626 × 10^(-34) J·s)
m is the mass of the object
v is the velocity of the object
Now, we can rearrange the equation to solve for mass (m):
m = h / (λ * v)
Given values:
λ (smallest measurable wavelength) = 0.330 fm = 0.330 × 10^(-15) m
v = 157 m/s
Substituting these values into the equation:
m = (6.626 × 10^(-34) J·s) / ((0.330 × 10^(-15) m) * (157 m/s))
Calculating this expression will give you the maximum mass of the object in kilograms that can be observed using the given setup.