How many milliliters of 0.524 M HNO3 contain 3.13 g HNO3?

mols HNO3 = grams HNO3/molar mass HNO3

Solve for mols HNO3.

Then mols = M x L. You know M and mols, solve for L and convert to mL.

To find the number of milliliters of 0.524 M HNO3 that contain 3.13 g of HNO3, we need to use the equation:

\( \text{Molarity (M)} = \frac{\text{moles of solute}}{\text{volume of solution (L)}} \)

First, let's calculate the number of moles of HNO3 using the given mass and the molar mass of HNO3.

The molar mass of HNO3 can be calculated by summing the molar masses of its individual atoms:

\( \text{molar mass of H} + \text{molar mass of N} + 3 \times \text{molar mass of O} = 1.008 + 14.007 + 3 \times 16.00 = 63.015 \, \text{g/mol} \)

To calculate the number of moles, we use the equation:

\( \text{moles of solute} = \frac{\text{mass of solute (g)}}{\text{molar mass of solute (g/mol)}} \)

\( \text{moles of HNO3} = \frac{3.13 \, \text{g}}{63.015 \, \text{g/mol}} \)

Simplifying, we find that the number of moles of HNO3 is approximately 0.0497 mol.

Now, we can rearrange the equation for molarity and solve for the volume of solution:

\( \text{volume of solution (L)} = \frac{\text{moles of solute}}{\text{Molarity (M)}} \)

\( \text{volume of solution (L)} = \frac{0.0497 \, \text{mol}}{0.524 \, \text{M}} \)

Finally, we need to convert the volume of the solution from liters to milliliters:

\( \text{volume of solution (mL)} = \text{volume of solution (L)} \times 1000 \)

Calculating, we find that the volume of 0.524 M HNO3 containing 3.13 g HNO3 is approximately 94.6 mL.