How to differentiate e^e^x?
Ans at wolfram is e^(x+e^x). I need the calculation method.

asked by Ifi
  1. You know that if y = e^u
    y' = e^u u'

    here, u=e^x, so
    y' = (e^e^x) (e^x)
    now just add exponents as usual when multiplying:

    y' = e^(e^x+x)

    posted by Steve

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