Triangle ABC has coordinates A(1, 4); B(3, –2); and C(4, 2). Find the coordinates of the image A'B'C' after a reflection over the x-axis?

I have never done one where the triangle is already over the x-axis...do we flip it up or down...
Please help me figure this out...

A(1,4) ---> A'(1,-4)

B(3,-2) --->B'(3,2)
C(4,2) ---> C'(4,-2)

Can you see what happened?
Plot he original and then the new one, use different colours to draw the lines of each triangle and notice the result.

Thank you so much - that really helped

yes thank you Reiny!!!

To find the coordinates of the image of each point after a reflection over the x-axis, you need to flip the triangle vertically. This means that the y-coordinates of each point will change sign while the x-coordinates remain the same.

Let's calculate the coordinates of the image points A', B', and C' after reflecting triangle ABC over the x-axis:

1. Point A(1, 4): To find A', we keep the x-coordinate the same, and change the sign of the y-coordinate. Therefore, A' has coordinates (1, -4).

2. Point B(3, -2): For B', we again keep the x-coordinate the same, and change the sign of the y-coordinate. Therefore, B' has coordinates (3, 2).

3. Point C(4, 2): Likewise, keeping the x-coordinate the same and changing the sign of the y-coordinate gives us C' with coordinates (4, -2).

Therefore, the coordinates of the image triangle A'B'C' after reflecting over the x-axis are A'(1, -4), B'(3, 2), and C'(4, -2).