A pound of body fat stores an amount of chemical energy equivalent to 3500 Cal (remember, 1 Calorie = 1 kilocalorie). When sleeping, the average adult burns or expends about 0.45 Cal/h for every pound of body weight. How long, in days, would the person have to sleep continuously to lose a pound of body fat?
To calculate the number of days it would take for a person to lose a pound of body fat while sleeping continuously, we need to determine how many calories are burned during sleep and then divide the total calorie deficit by the number of calories burned per day.
Given that the average adult burns 0.45 Cal/h for every pound of body weight, we can calculate the calorie deficit during sleep per pound of body weight as follows:
Caloric deficit per pound of body weight during sleep = 0.45 Cal/hour * 24 hours/day = 10.8 Cal/pound.
Since a pound of body fat stores 3500 Cal of energy, we can determine the number of days required to burn this amount of energy during sleep:
Number of days = Total calorie deficit / Caloric deficit per pound of body weight during sleep
= 3500 Cal / 10.8 Cal/pound
≈ 324.07 days.
Therefore, it would take approximately 324.07 days (or rounded up to 325 days) of continuous sleep to lose a pound of body fat.
To find out how long a person would have to sleep continuously to lose a pound of body fat, we need to calculate the total number of calories burned during sleep and then divide it by the number of calories stored in a pound of body fat.
First, we need to convert the calorie rate from pounds to kilograms. Since 1 pound is approximately 0.45 kilograms, we multiply 0.45 by 0.45 Cal/h to convert it to kilograms per hour. So, the rate becomes 0.45 * 0.45 Cal/h ≈ 0.2025 Cal/h.
Next, we need to calculate the total number of calories burned during sleep per day. Assuming a person sleeps for 8 hours (which is the average), we multiply the calorie rate by the number of hours: 0.2025 Cal/h * 8 hours = 1.62 Cal/day.
Now, we can determine the number of days needed to burn a pound of body fat. Given that 1 pound of body fat stores 3500 Cal, we divide 3500 Cal by 1.62 Cal/day:
3500 Cal / 1.62 Cal/day ≈ 2160.49 days.
Rounded to the nearest whole number, the person would have to sleep continuously for approximately 2160 days to lose a pound of body fat.
Remember, this calculation assumes that all the weight loss occurs from burning body fat alone and does not account for other factors such as metabolism, muscle mass, etc.
0.45 Cal/hr x 24 hr = 10.8 Cal/day.
10.8 Cal/day x ? day = 3500 = ?
Hello Rip Van Winkle.