Algebra II (check)
 👍
 👎
 👁

 👍
 👎
Respond to this Question
Similar Questions

math
A=1/2h (b1 + b2) Solve for b1 A=1/2h (b1 + b2) Solve for b1 I assume this is A = (1/2)(h)(b1 + b2); i.e., the h is in the numerator and not the denominator Multiply both sides by 2. 2A = (2*1/2)h(b1 + b2). 2*1/2 on the right side

math
Match the equation with the step needed to solve it. 1. 2m  1 = 3m subtract m 2. 2m = 1 + m subtract 2 3. m  1 = 2 subtract 1 4. 2 + m = 3 subtract 2m 5. 2 + m = 1 add 2 6. 3 = 1 + m add 1

MATH
1. 42 Add 5 to both sides, then add 3, then add (4) 3. 4

Algebra
The first step to solve for y in y/3= 6 + x is A) to subtract x from both sides of the equation. B) to subtract y/3 from both sides of the equation. C) to divide each term on both sides of the equation by 3. ******* D) to multiply

Variable
SOLVING EQUATIONS WITH THE VARIABLE ON BOTH SIDES Solve the equation. Then check your solution. 4x9 = 7x+12 Just remember that one can add, subtract, multiply, divide, etc but whatever is done to one side must be done to the

algebra
Which could be a first step in solving the equation 1/4x+1/2=3/4x in an efficient way? Select two answers. A.multiply by 4 on both sides B.multiply by 2x on both sides C.subtract 1/4x from both sides D.add 1/2 to both sides plz

Math
Which could be a first step in solving the equation 1/4x + 1/2 = 3/4x in an efficient way? Select two answers. multiply by 4 on both sides multiply by 2x on both sides subtract 1/4x from both sides add 1/2 to both sides

Math
Which could be a first step in solving the equation 1/4x + 1/2 = 3/4x in an efficient way? Select two answers. A. Multiply by 4 on both sides*** B. Multiply by 2x on both sides C. Subtract 1/4x from both sides D. Add 1/2 to both

Algebra
Which of the following describes a correct method for solving the equation below? 7/2n + 5 = 16 1. add 5 to both sides, then divide both sides by 2/7 2. subtract 5 from both sides, then multiply both sides by 7/2 3. add 5 to

Algebra
Solve Q= (NS)/ N for N So when I multiply both sides by N I get Q(N)= NS I know I am doing something wrong, the answer is in the book which is N=S/(1Q)but I don't understand were the 1 comes from. Could you write it out step by

Algebra 2
Simplify, (2 sqrt3x^5  2sqrt y)^2

Maths
Limit x approches 1(sqrt(1+2x)(sqrt3x))/(sqrt(3+x)2sqrt(x))
You can view more similar questions or ask a new question.