1.given the function y=x^2-4x+5,find the following:
a.vertex
b.maximum or minimum
c.axis of symmetry
d.y-intercept
e.x-intercept(zeros)
f.graph
complete the square ....
y = x^2 - 4x + 4 - 4 + 5
= (x-2)^2 + 1
vertex is (2,1)
opens up, so minimum
axis of symmetry: x = 2
y-intercepts: let x = 0, y = 5
x-intercepts:
let y = 0
x^2 - 4x+ 5 = 0
(x-5)(x+1) = 0
x = 5, x = -1 , notice the x of the vertex is midway between these.
graph: you do it.