The specific heat of zinc is 0.386 J/g degrees Celsius. How many joules would be released when 454 grams of Zinc at 96.0 degrees Celsius were cooled to 28.0 degrees Celsius.
To calculate the amount of heat released when cooling the zinc, we can use the formula:
Q = m * C * ΔT
Where:
Q = amount of heat released (in joules)
m = mass of the substance (in grams)
C = specific heat of the substance (in J/g°C)
ΔT = change in temperature (in °C)
Given:
m = 454 grams
C = 0.386 J/g°C
ΔT = 96.0°C - 28.0°C = 68.0°C
Now we can substitute these values into the formula and calculate the amount of heat released:
Q = 454 g * 0.386 J/g°C * 68.0°C
Q = 11357.648 J
Therefore, 11357.648 joules (rounded to three decimal places) would be released when 454 grams of zinc at 96.0 degrees Celsius is cooled to 28.0 degrees Celsius.
To calculate the amount of energy released when cooling a substance, we can use the formula:
Q = m * c * ΔT
Where:
Q is the amount of energy released (in Joules)
m is the mass of the substance (in grams)
c is the specific heat capacity of the substance (in J/g°C)
ΔT is the change in temperature (in °C)
In this case, we have:
m = 454 grams (mass of zinc)
c = 0.386 J/g°C (specific heat of zinc)
ΔT = 96.0°C - 28.0°C = 68.0°C (change in temperature)
Now, we can substitute these values into the formula and calculate the energy released:
Q = 454 g * 0.386 J/g°C * 68.0°C
Q = 12514.0 Joules
Therefore, 12514.0 Joules would be released when 454 grams of zinc at 96.0 degrees Celsius are cooled to 28.0 degrees Celsius.