Calculate the number of Joules released when 75.0 g of water are cooled from 100.0 degrees Celsius to 27.5 degrees Celsius

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2000

To calculate the number of joules released when 75.0 g of water are cooled from 100.0 degrees Celsius to 27.5 degrees Celsius, you can use the specific heat capacity equation:

q = m × c × ΔT

where:
q is the amount of heat released (in joules),
m is the mass of the substance (in grams),
c is the specific heat capacity of the substance (in J/g°C), and
ΔT is the change in temperature (in °C).

First, you need to determine the specific heat capacity of water, which is approximately 4.184 J/g°C.

Next, calculate the change in temperature by subtracting the final temperature from the initial temperature:

ΔT = 27.5°C - 100.0°C = -72.5°C

Note: The change in temperature is negative because the water is being cooled.

Now you can substitute the values into the equation:

q = 75.0 g × 4.184 J/g°C × -72.5°C

Simplifying the equation:

q = -227,295 J

Therefore, approximately -227,295 joules (J) of heat are released when 75.0 g of water are cooled from 100.0 degrees Celsius to 27.5 degrees Celsius. The negative sign indicates heat release.