Calculate the heat in joules needed to warm 225g of water from 88.0 degrees Celsius to its boiling point 100.0 degrees Celsius
q = mass H2O x specific heat H2O x (Tfinal-Tinitial).
To calculate the heat in joules needed to warm a substance, we can use the formula:
Q = mass × specific heat capacity × change in temperature
First, we need to calculate the change in temperature. The initial temperature is 88.0 degrees Celsius, and the final temperature is 100.0 degrees Celsius. So, the change in temperature is:
ΔT = final temperature - initial temperature
ΔT = 100.0°C - 88.0°C
ΔT = 12.0°C
Next, we need to determine the specific heat capacity of water. The specific heat capacity of water is 4.18 J/g°C.
Now, we can substitute the values into the formula:
Q = mass × specific heat capacity × change in temperature
Q = 225g × 4.18 J/g°C × 12.0°C
Calculating this expression:
Q = 1121.5 Joules
Therefore, the heat needed to warm 225g of water from 88.0 degrees Celsius to its boiling point 100.0 degrees Celsius is 1121.5 Joules.