There are nine coins on the table , 5 nickels , 3 quarters and 1 dime. Tom , Bill and Drew each pick up three coins. Bill has 25 cent more than Tom. Drew has as much money as Tom and Bill together . What three coins Drew to pick up?
my answer: Drew ===)2 quarters+i nickel
Is it correct. Please help me. thanks
I think your right
To determine which three coins Drew picked up, let's break down the given information step by step:
1. There are a total of 9 coins on the table: 5 nickels, 3 quarters, and 1 dime. So, the coins Drew picked up cannot include the dime, as it wasn't mentioned.
2. Bill has 25 cents more than Tom. This means that Bill must have either 2 quarters and 1 nickel or 1 quarter and 2 nickels. Let's consider both possibilities:
Possibility 1: Bill has 2 quarters and 1 nickel:
- Tom would then have 1 quarter and 2 nickels.
- The combined value of Bill's coins would be 50 cents + 25 cents (25 cents more than Tom) = 75 cents.
Possibility 2: Bill has 1 quarter and 2 nickels:
- Tom would then have 2 quarters and 1 nickel.
- The combined value of Bill's coins would be 25 cents + 10 cents (25 cents more than Tom) = 35 cents.
3. Drew has as much money as Tom and Bill together. Let's analyze both possibilities mentioned above:
For Possibility 1:
- If Drew has 75 cents, it would require at least 3 quarters, which is not possible as there are only 3 quarters on the table.
- Therefore, Drew cannot have 2 quarters in this case.
For Possibility 2:
- If Drew has 35 cents, it could be a combination of 2 quarters and 1 nickel, as 25 cents + 25 cents + 5 cents = 55 cents.
- Therefore, Drew could have picked up 2 quarters and 1 nickel.
Based on the analysis, it seems that your answer is correct:
Drew picked up 2 quarters and 1 nickel.