How long will it take a car traveling 65 mph to pass a car traveling 45 mph if the slower car had a 2 hour lead?

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To find out how long it will take for the faster car to pass the slower car, we need to calculate the distance traveled by both cars.

First, let's calculate the distance traveled by the slower car during the 2-hour lead. The formula to calculate distance is speed multiplied by time:

Distance of slower car = Speed of slower car × Time = 45 mph × 2 hours = 90 miles.

Now, let's consider the point when the faster car catches up with the slower car. At this point, both cars will have traveled the same distance.

Let's assume the time it takes for the faster car to catch up is 't' hours.

Distance traveled by the faster car = Speed of faster car × Time = 65 mph × t.

Since the distance traveled by both cars is equal when they meet, we can equate these two distances:

90 miles = 65 mph × t.

To find 't', we can rearrange the equation:

t = 90 miles / 65 mph ≈ 1.38 hours.

So, it will take approximately 1.38 hours for the faster car to pass the slower car after the 2-hour lead.

Note: If you prefer to convert this time to minutes or seconds, you can do so by multiplying by 60 (for minutes) or 3,600 (for seconds).