A sample of helium occupies 1521 mL at 719 mmHg. Assume that the temperature is held constant and determine
a) the volume of the helium at mmHg.
b)the pressure, in mmHg, if the volume is changed to 315mL
You omitted the number for a but what you want is P1V1 = P2V2. Substitute and solve for the unknown v.
b. Use P1V1 = P2V2 again. Substitute and solve for the unknown.
u777
To solve this problem, we can use Boyle's Law, which states that the product of pressure and volume is constant when temperature is held constant.
a) To find the volume of helium at a different pressure, we can set up the following equation:
P1 * V1 = P2 * V2
where P1 and V1 are the initial pressure and volume, and P2 and V2 are the final pressure and volume.
Given that the initial volume is 1521 mL and the initial pressure is 719 mmHg, we can plug in the values into the equation:
(719 mmHg) * (1521 mL) = (P2) * (V2)
Now, let's solve for V2:
V2 = (719 mmHg * 1521 mL) / P2
b) To find the pressure at a different volume, we can rearrange the equation as follows:
P1 * V1 = P2 * V2
P2 = (P1 * V1) / V2
Given that the initial volume is 1521 mL, the initial pressure is 719 mmHg, and the final volume is 315 mL, we can plug in the values into the equation:
P2 = (719 mmHg * 1521 mL) / 315 mL
Now, let's solve for P2.
To solve both parts of the question, we can use Boyle's Law, which states that the product of pressure and volume remains constant as long as the temperature is constant.
Boyle's Law equation:
P₁V₁ = P₂V₂
where:
P₁ = initial pressure
V₁ = initial volume
P₂ = final pressure
V₂ = final volume
Now let's solve each part:
a) To find the volume of the helium at a different pressure, we have the following information:
Initial volume (V₁) = 1521 mL
Initial pressure (P₁) = 719 mmHg
Final pressure (P₂) = ? (mmHg)
Since we want to find the volume at mmHg, we can rearrange Boyle's Law equation to solve for P₂:
P₂ = (P₁ * V₁) / V₂
Substituting the given values, we get:
P₂ = (719 mmHg * 1521 mL) / V₂
b) To find the pressure at a different volume, we have the following information:
Initial volume (V₁) = 1521 mL
Initial pressure (P₁) = 719 mmHg
Final volume (V₂) = 315 mL
Final pressure (P₂) = ? (mmHg)
Again, using Boyle's Law equation:
P₁V₁ = P₂V₂
Substituting the given values, we can solve for P₂:
719 mmHg * 1521 mL = P₂ * 315 mL
Now, isolate P₂:
P₂ = (719 mmHg * 1521 mL) / 315 mL
By substituting the given values into the respective equations, you can calculate the answers for both parts of the question.