Question

Assume that no denominator equals 0.

(8y^3+27)/(2xy-10y+3x-15)

I don't know how to solve this one.

Answer 1

You will have to factor both top and bottom and then reduce

your text should have a rule for the sum of cubes
(A^3 + B^3) = (A+B)(A^2 - AB + b^2)

so the top factors to
(2y+3)(4y^2 - 6y + 9)

the bottom factors by grouping to

(x-5)(2y+3)

so after you cancel you would have

(x-5)/(4y^2 - 6y + 9)