Assume that no denominator equals 0.
(2x-3)^2
= 2x * 2x -3 * -3
= 4x-9(answer)
no
(2x-3)^2 means (2x-3)(2x-3) which is
4x^2 - 6x - 6x + 9
= 4x^2 - 12x + 9
wouldn't it be 4x^2 + 12x + 9?
why?
-6 -6 = -12
(you borrow $6 from your mom, and then borrow $6 more, how much do you owe her?)
ok I was thinking about multiplication
Actually, the simplification of the expression (2x-3)^2 is not correct. Let me help you with the correct simplification.
To expand the square of a binomial, such as (2x-3)^2, you need to apply the formula (a-b)^2 = a^2 - 2ab + b^2. In this case, a = 2x and b = 3.
So, substituting these values into the formula, we have:
(2x-3)^2 = (2x)^2 - 2(2x)(3) + (3)^2
Now, we can simplify each term:
(2x)^2 = 4x^2 (squaring 2x)
- 2(2x)(3) = -12x (multiplying -2, 2x, and 3)
(3)^2 = 9 (squaring 3)
Putting it all together, we get:
(2x-3)^2 = 4x^2 - 12x + 9
Therefore, the simplified expression is 4x^2 -12x + 9.